This document covers topics in generating random samples of combinations/permutations. It is encouraged to read General Combinatorics first.
To illustrate this in base R
, let us consider getting 5 random combinations of the vector 1:20
of length 10. How should we proceed?
A naive approach would be to generate all of the combinations using combn
and then call sample
:
naive <- function(v, m, n, s) {
allCombs <- combn(v, m)
set.seed(s)
allCombs[, sample(ncol(allCombs), n)]
}
fiveRndCombs <- naive(20, 10, 5, 42)
t(fiveRndCombs)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] 4 5 7 8 9 11 13 14 17 18
[2,] 4 6 7 10 11 12 13 14 15 16
[3,] 1 3 4 7 9 11 14 15 17 20
[4,] 3 4 9 10 11 12 14 18 19 20
[5,] 2 4 5 6 8 11 12 16 17 20
This is okay for this small example (there are only choose(20, 10) = 184756
results), however what if we wanted to find one hundred thousand random combinations from the vector 1:100
of length 20? Clearly, the approach above will not be feasible as there are far too many results to generate (choose(100, 20) = 5.359834e+20
). Furthermore, there are internal limitations on sample
. If we try to pass choose(100, 20)
, we will get an error:
We could also try calling sample(100, 20)
a bunch of times and hope we don’t get duplicate combinations. This is neither promising nor elegant.
RcppAlgos
provides three functions: comboSample
, permuteSample
, and comboGroupsSample
for seamlessly attacking these types of problems. All functions provide the following:
sample
when the total number of results is small and for larger cases, the sampling is done in a very similar fashion to urand.bigz
from the gmp
package.combo/permuteGeneral
and comboGroups
)seed
parameter must be set in order to have reproducible results (E.g. set.seed()
) has no effect in these cases).comboSample
and permuteSample
Let’s first look at the first problem above (i.e. getting 5 random combinations of the vector 1:20
of length 10):
library(RcppAlgos)
set.seed(42)
comboSample(20, 10, n = 5)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] 4 5 7 8 9 11 13 14 17 18
[2,] 4 6 7 10 11 12 13 14 15 16
[3,] 1 3 4 7 9 11 14 15 17 20
[4,] 3 4 9 10 11 12 14 18 19 20
[5,] 2 4 5 6 8 11 12 16 17 20
## Use the seed argument directly to produce the same output
comboSample(20, 10, n = 5, seed = 42)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] 4 5 7 8 9 11 13 14 17 18
[2,] 4 6 7 10 11 12 13 14 15 16
[3,] 1 3 4 7 9 11 14 15 17 20
[4,] 3 4 9 10 11 12 14 18 19 20
[5,] 2 4 5 6 8 11 12 16 17 20
## fiveRndCombs produced above
identical(t(fiveRndCombs),
comboSample(20, 10, n = 5, seed = 42))
[1] TRUE
Just like with comboGeneral
and permuteGeneral
, we can explore results with repetition.
comboSample(10, 8, TRUE, n = 3, seed = 84)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
[1,] 3 3 3 6 6 10 10 10
[2,] 1 3 3 4 4 7 9 10
[3,] 3 7 7 7 9 10 10 10
permuteSample(10, 8, TRUE, n = 3)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
[1,] 8 7 8 10 1 2 7 6
[2,] 3 3 8 10 2 4 4 6
[3,] 3 7 8 4 2 9 10 4
comboSample(10, 12, freqs = 1:10, n = 3)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12]
[1,] 1 2 3 4 5 5 6 8 8 9 10 10
[2,] 1 4 4 4 5 5 5 5 5 7 7 7
[3,] 2 3 4 5 5 6 7 7 7 7 7 7
permuteSample(10, 12, freqs = 1:10, n = 3, seed = 123)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12]
[1,] 4 6 7 7 1 10 8 7 8 7 4 6
[2,] 5 7 7 8 7 7 2 5 5 3 4 2
[3,] 10 6 1 10 8 5 3 9 7 2 9 3
sampleVec
We can also utilize sampleVec
to generate specific results.
## E.g. the below generates the 1st, 5th, 25th, 125th, and
## 625th lexicographical combinations
comboSample(10, 8, TRUE, sampleVec = c(1, 5, 25, 125, 625))
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
[1,] 1 1 1 1 1 1 1 1
[2,] 1 1 1 1 1 1 1 5
[3,] 1 1 1 1 1 1 3 8
[4,] 1 1 1 1 1 3 6 9
[5,] 1 1 1 1 5 6 10 10
## Is the same as:
comboGeneral(10, 8, TRUE)[5^(0:4), ]
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
[1,] 1 1 1 1 1 1 1 1
[2,] 1 1 1 1 1 1 1 5
[3,] 1 1 1 1 1 1 3 8
[4,] 1 1 1 1 1 3 6 9
[5,] 1 1 1 1 5 6 10 10
namedSample
Have you ever wondered which lexicographical combinations/permutations are returned when sampling? No worries, simply set namedSample = TRUE
:
testInd <- permuteSample(30, 10, n = 3, seed = 100, namedSample = TRUE)
testInd
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
33554924331145 10 7 24 5 29 6 30 12 16 11
60218249947169 17 18 15 19 14 2 1 4 7 29
51084688265260 15 2 20 27 8 10 25 30 3 18
## Same output as above
permuteSample(30, 10, sampleVec = row.names(testInd))
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] 10 7 24 5 29 6 30 12 16 11
[2,] 17 18 15 19 14 2 1 4 7 29
[3,] 15 2 20 27 8 10 25 30 3 18
Just like the General
counterparts, the sampling functions utilize GMP to allow for exploration of combinations/permutations of large vectors where the total number of results is enormous. They also offer parallel options using Parallel
or nThreads
.
## Uses min(stdThreadMax() - 1, 5) threads (in this case)
permuteSample(500, 10, TRUE, n = 5, seed = 123, Parallel = TRUE)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] 55 435 274 324 200 152 6 313 121 377
[2,] 196 166 331 154 443 329 155 233 354 442
[3,] 235 325 94 27 370 117 302 86 229 126
[4,] 284 104 464 104 207 127 117 9 390 414
[5,] 456 76 381 456 219 23 376 187 11 123
permuteSample(factor(state.abb), 15, n = 3, seed = 50, nThreads = 3)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14] [,15]
[1,] ME FL DE OK ND CA PA AL ID MO NM HI KY MT NJ
[2,] AZ CA AL CT ME SD ID SC OK NH HI TN ND IA MT
[3,] MD MO NC MT NH AL VA MA VT WV NJ NE MN MS MI
50 Levels: AK AL AR AZ CA CO CT DE FL GA HI IA ID IL IN KS KY LA MA MD ME MI MN ... WY
permuteCount(factor(state.abb), 15)
Big Integer ('bigz') :
[1] 2943352142120754524160000
The algorithms are incredibly efficient and offer tremendous gains over the naive approach above:
## the function "naive" is defined above
system.time(naive(25, 10, 5, 15))
user system elapsed
3.526 0.065 3.604
system.time(comboSample(25, 10, n = 5, seed = 15))
user system elapsed
0.002 0.000 0.001
Even when dealing with extremely large numbers, these algorithms are very fast. And using the parallel options have even greater effects than we saw with the general counterparts (typically around ~2-3 times faster with the general functions, whereas with the last example below with sampling we see a nearly 5 fold improvement).
## Lightning fast even with examples involving many results
system.time(comboSample(2500, 100, n = 5, seed = 15))
user system elapsed
0.002 0.000 0.002
## The total number of combinations has ~180 digits
gmp::log10.bigz(comboCount(2500, 100))
[1] 180.9525
## Still fast with larger samples
system.time(comboSample(2500, 100, n = 1e4, seed = 157))
user system elapsed
1.482 0.006 1.491
## Using Parallel/nThreads in these cases has an even greater effect
system.time(comboSample(2500, 100, n = 1e4, seed = 157, nThreads = 8))
user system elapsed
2.409 0.002 0.310
Again, just as with the general functions, you can pass a custom function to combo/permuteSample
using the FUN
argument.
permuteSample(5000, 1000, n = 3, seed = 101, FUN = sd)
[[1]]
[1] 1431.949
[[2]]
[1] 1446.859
[[3]]
[1] 1449.272
## Example using complex numbers
myCplx <- as.complex(1:100 + rep(c(-1, 1), 50) * 1i)
permuteSample(myCplx, 10, freqs = rep(1:5, 20),
n = 3, seed = 101, FUN = function(x) {
sqrt(sum(x))
})
[[1]]
[1] 24.83948+0i
[[2]]
[1] 20.9285+0.04778i
[[3]]
[1] 22.20379+0.09007i
comboGroupsSample
Just as we can generate random samples of combinations and permutations, we are also able to generate random samples of partitions of groups of equal size.
There are many problems that present in this manner. Below, we examine one involving playing cards.
Let’s say we have 4 players and each player is to have 3 cards a piece. Given that the deck is shuffled, the dealer then distrubutes 12 cards.
What possible hands can each player have?
See Creating A Deck Of Cards In R Without Using While And Double For Loop (Credit to @MichaelChirico)
cards <- c(2:10, "J", "Q", "K", "A")
suits <- c("♠", "♥", "♦", "♣")
deck <- paste0(rep(cards, length(suits)), #card values
rep(suits, each = length(cards))) #suits
set.seed(1738)
shuffled <- factor(deck[sample(52)], levels = deck)
## Here are 3 possibilities
comboGroupsSample(shuffled[1:12], numGroups = 4, n = 2, seed = 13)
Grp1 Grp1 Grp1 Grp2 Grp2 Grp2 Grp3 Grp3 Grp3 Grp4 Grp4 Grp4
[1,] A♠ 2♥ 6♠ 10♦ 10♥ J♣ 8♠ 10♣ 3♠ Q♦ 6♣ 8♦
[2,] A♠ 10♥ Q♦ 10♦ 2♥ 8♦ 8♠ J♣ 6♣ 10♣ 3♠ 6♠
52 Levels: 2♠ 3♠ 4♠ 5♠ 6♠ 7♠ 8♠ 9♠ 10♠ J♠ Q♠ K♠ A♠ 2♥ 3♥ 4♥ 5♥ 6♥ 7♥ 8♥ ... A♣
comboGroupsSample(shuffled[1:12], numGroups = 4, retType = "3Darray",
n = 2, seed = 13, namedSample = TRUE)
, , Grp1
[,1] [,2] [,3]
10939 A♠ 2♥ 6♠
3791 A♠ 10♥ Q♦
, , Grp2
[,1] [,2] [,3]
10939 10♦ 10♥ J♣
3791 10♦ 2♥ 8♦
, , Grp3
[,1] [,2] [,3]
10939 8♠ 10♣ 3♠
3791 8♠ J♣ 6♣
, , Grp4
[,1] [,2] [,3]
10939 Q♦ 6♣ 8♦
3791 10♣ 3♠ 6♠
52 Levels: 2♠ 3♠ 4♠ 5♠ 6♠ 7♠ 8♠ 9♠ 10♠ J♠ Q♠ K♠ A♠ 2♥ 3♥ 4♥ 5♥ 6♥ 7♥ 8♥ ... A♣